If we list all the natural numbers below 10 that are multiples of 3 or 5, we get 3, 5, 6 and 9. The sum of these multiples is 23.
Find the sum of all the multiples of 3 or 5 below 1000.
cevap : 233168
clear all;
clc;
close all;
sum = 0;
for i=1:999
if (mod(i,3) == 0)
sum = sum + i;
end
if(mod(i,5) == 0)
sum = sum + i;
end
if(mod(i,15) == 0)
sum = sum - i;
end
end